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6n^2-10=56
We move all terms to the left:
6n^2-10-(56)=0
We add all the numbers together, and all the variables
6n^2-66=0
a = 6; b = 0; c = -66;
Δ = b2-4ac
Δ = 02-4·6·(-66)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{11}}{2*6}=\frac{0-12\sqrt{11}}{12} =-\frac{12\sqrt{11}}{12} =-\sqrt{11} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{11}}{2*6}=\frac{0+12\sqrt{11}}{12} =\frac{12\sqrt{11}}{12} =\sqrt{11} $
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